if a number is repeated 2 or its multiplied no of times then it will be divided by 11
if a number is repeated 6 or its multiplied no of times then it will be divided by 3/7/11/13/37
if two number is repeated 3 or its multiplied no of times then it will be divided by 3/7/13/37
if 0 is repeated at-least 2 times at the last then it will be divided by 4
if 0 is repeated at-least 3 times at the last then it will be divided by 8
(we know the every rules but when the combination is used then we forgot about these formulas)
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EX:-
#) 44444....4 here 4 is repeated 429 times.if it is divided by 1144.then what will be the remainder?
Ans:- here 1144=8*11*13
now 4444....4 if it is repeated 426 times and the last three digits are 000
then this will be divided by 1144 or (11*13*8) as 426 divided by 6 and as last three digits are 0 so it will be divided by 8
so remainder is 444
#) 1212...12 here 12 is repeated 283 times.if it is divided by 1036. then what will be the remainder?
Ans:- here 1036= 4*7*37
now 1212...12 if it is repeated 282 times and the last two digits are 00
then this will be divided by 1036 or (4*7*37) as 282 is divided by 3 and as last two digits are 0 so it will be divided by 4
so remainder is 12
if a number is repeated 6 or its multiplied no of times then it will be divided by 3/7/11/13/37
if two number is repeated 3 or its multiplied no of times then it will be divided by 3/7/13/37
if 0 is repeated at-least 2 times at the last then it will be divided by 4
if 0 is repeated at-least 3 times at the last then it will be divided by 8
(we know the every rules but when the combination is used then we forgot about these formulas)
.............................................................................................................................
EX:-
#) 44444....4 here 4 is repeated 429 times.if it is divided by 1144.then what will be the remainder?
Ans:- here 1144=8*11*13
now 4444....4 if it is repeated 426 times and the last three digits are 000
then this will be divided by 1144 or (11*13*8) as 426 divided by 6 and as last three digits are 0 so it will be divided by 8
so remainder is 444
#) 1212...12 here 12 is repeated 283 times.if it is divided by 1036. then what will be the remainder?
Ans:- here 1036= 4*7*37
now 1212...12 if it is repeated 282 times and the last two digits are 00
then this will be divided by 1036 or (4*7*37) as 282 is divided by 3 and as last two digits are 0 so it will be divided by 4
so remainder is 12
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